Linux – multiples ip on interface. i wish to specify one of these for output – server fault

I ran curl on curlmyip.com, and that i got the incorrect output ip.

My systemd service file is:

[Unit]

Description=Wired Networking

Wants=network.target dibbler-client.service

Before=network.target dibbler-client.service

[Service]

Type=oneshot

RemainAfterExit=yes

EnvironmentFile=/etc/conf.d/network

ExecStart=/sbin/ip link set dev $ up

ExecStart=/sbin/ip addr add $/24 dev $

ExecStart=/sbin/ip addr add $/32 dev $

ExecStart=/sbin/ip route add default via $ src $

ExecStart=/sbin/ip -6 addr add $/64 dev $

ExecStop=/sbin/ip addr flush dev $

ExecStop=/sbin/ip -6 addr flush dev $

ExecStop=/sbin/ip link set dev $ lower

[Install]

WantedBy=multi-user.target

And variables are:

interface=eno1

address=88.190.15.135

address6=2001:bc8:300a:dead::b12d

failover=212.83.129.104

broadcast=88.190.15.255

gateway=88.190.15.1

Now, ip addr produce:

1: lo: mtu 65536 qdisc noqueue condition UNKNOWN

link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00

inet 127…1/8 scope host lo

valid_lft forever preferred_lft forever

inet6 ::1/128 scope host

valid_lft forever preferred_lft forever

2: eno1: mtu 1500 qdisc mq condition UP qlen 1000

link/ether b8:ac:6f:94:e2:4e brd ff:ff:ff:ff:ff:ff

inet 88.190.15.135/24 scope global eno1

valid_lft forever preferred_lft forever

inet 212.83.129.104/32 scope global eno1

valid_lft forever preferred_lft forever

inet6 fe80::baac:6fff:fe94:e24e/64 scope link

valid_lft forever preferred_lft forever

and ip route:

default via 88.190.15.1 dev eno1 src 212.83.129.104

88.190.15./24 dev eno1 proto kernel scope link src 88.190.15.135

I ran curl on curlmyip.com, and that i got the incorrect output ip.

My systemd service file is:

[Unit]

Description=Wired Networking

Wants=network.target dibbler-client.service

Before=network.target dibbler-client.service

[Service]

Type=oneshot

RemainAfterExit=yes

EnvironmentFile=/etc/conf.d/network

ExecStart=/sbin/ip link set dev $ up

ExecStart=/sbin/ip addr add $/24 dev $

ExecStart=/sbin/ip addr add $/32 dev $

ExecStart=/sbin/ip route add default via $ src $

ExecStart=/sbin/ip -6 addr add $/64 dev $

ExecStop=/sbin/ip addr flush dev $

ExecStop=/sbin/ip -6 addr flush dev $

ExecStop=/sbin/ip link set dev $ lower

[Install]

WantedBy=multi-user.target

And variables are:

interface=eno1

address=88.190.15.135

address6=2001:bc8:300a:dead::b12d

failover=212.83.129.104

broadcast=88.190.15.255

gateway=88.190.15.1

Now, ip addr produce:

1: lo: mtu 65536 qdisc noqueue condition UNKNOWN

link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00

inet 127…1/8 scope host lo

valid_lft forever preferred_lft forever

inet6 ::1/128 scope host

valid_lft forever preferred_lft forever

2: eno1: mtu 1500 qdisc mq condition UP qlen 1000

link/ether b8:ac:6f:94:e2:4e brd ff:ff:ff:ff:ff:ff

inet 88.190.15.135/24 scope global eno1

valid_lft forever preferred_lft forever

inet 212.83.129.104/32 scope global eno1

valid_lft forever preferred_lft forever

inet6 fe80::baac:6fff:fe94:e24e/64 scope link

valid_lft forever preferred_lft forever

and ip route:

default via 88.190.15.1 dev eno1 src 212.83.129.104

88.190.15./24 dev eno1 proto kernel scope link src 88.190.15.135

curlmyip.com let me know the output ip is 88.190.15.135. How do i change this output address making it 212.83.129.104?

EDIT: tested to alter the src from the path to the gateway… No changes.

Thanks!

Resourse: https://serverfault.com/questions/542424/

Python Network Programming 10 – Multiple Client ( Socket Programming )